______device is provided to prevent starting air from being admitted to the cylinder befor
A.An automatic
B.A transmission
C.A self-regulating
D.An interlocking
A.An automatic
B.A transmission
C.A self-regulating
D.An interlocking
第3题
A.SELECT PROV FROM S WHERE SD='信息系'
B.SELECT ALL PROV FROM S WHERE SD='信息系'
C.SELECT DISTINCT PROV FROM S WHERE SD='信息系'
D.SELECT PROV FROM S WHERE '信息系'=SD
第4题
A.SELECT PROV FROM S WHERE SD='信息系'
B.SELECT ALL PROV FROM S WHERE SD='信息系'
C.SELECT DISTINCT PROV FROM S WHERE SD='信息系'
D.SELECT PROV FROM S WHERE '信息系'=SD
第5题
已知学生表S、学生选课表SC,结构如下: S(S#,SN,SD,PROV) SC(S#,CN,GR) 其中S#为学号,SN为姓名,SD为系别,PROV为省区,CN为课程名,GR为成绩 请写出完成以下任务需要的SQL语句:1)查询'信息系'的学生来自哪些省区。2)按分数降序排序,输出'英语系'学生中选修了'计算机'课程的学生的姓名和成绩。
第6题
A.College career offices
B.State Department of Labour offices
C.The local public library
D.All of the abov
第7题
阅读以下说明和java代码,将应填入(n)处的字句写在对应栏内。
[说明]
本程序使用类来管理员工的通讯地址信息。已知程序的输出为:
输出记录:5
姓名:王丽华
街道地址:中华路15号
市:襄樊市
省:湖北省
邮政编码:430070
[Java代码]
public class Employee{
protected String (1);
protected String street;
protected String city;
protected String prov;
protected String post;
protected int no;
public Empbyee(){}
public Employee(String name,String street,String city,String prov,String post, (2) ){
this.name=name;
this.street=street;
this.city=city;
this.prov=prov;
this.post=post;
this.no=no;
}
public static void main(String[]args){
Employee emp=new Employee(“王华”,“中华路15号”,“武汉市”,“湖北省”,“430070”,1);
emp.changeName(“王丽华”);
(3) (“襄樊市”);
emp.changeNo(5);
(4);
}
void changeName(String name){this.name=name;}
void changeStreet(String street){this.street=street;}
void changeCity(String city){this.city=city;}
void changeProv(String prov){this.prov=prov;}
void changeNo(int no){(5);}
void display(){
System.out.println(“输出记录:”+this.no);
System.out.Println(“姓名:”+this.name);
System.out.println(“街道地址:”+this.street);
System.out.println(“市:”+this.city);
System.out.println(“省:”+this.prov);
System.out.println(“邮政编码:”+this.post);
}
}
第8题
(1)补充类Employee的构造函数,请使用字符串函数将数据成员name,address,city,province和zipcode分别初始化为参数*nm,*addr,*city,*prov和*zip的值。请在注释“//**1**”之后添加适当的语句;
(2)完成类Employee的成员函数ChangeName(char * newName)的定义,将newName指向的内容赋值给数据成员name,请在注释“//**2**”之后添加适当的语句;
(3)完成类Employee的成员函数Display()的定义,先使用指针buffer动态申请一个char型的200单位大小的空间,然后使用字符串函数将数据成员name和address依次复制其中,最后返回该指针buffer,将请在注释“//**3**”之后添加适当的语句。输出结果如下:
王东建国路大街105号
注意:除在指定位置添加语句之外,请不要改动程序中的其他内容。
源程序文件test18_3.cpp清单如下:
include <iostream.h>
include <string.h>
class Employee{
protected:
char name[20];
char address[100];
char city[20];
char province[20];
char zipcode[10];
public:
Employee(char *nm, char *addr,char *city, char *prov, char *zip);
void ChangeName(char *newName);
char *Display();
};
Employee::Employee(char *nm, char *adr, char *cit, char *prov, char *zip)
{
//**1**
strcpy(city, cit);
strcpy(province,prov);
strcpy(zipcode,zip);
}
void Employee::ChangeName(char * newName)
{
//**2**
}
char *Employee::Display()
{
//**3**
strcat(buffer, address);
return buffer;
}
void main()
{
Employee emp("李华","建国路大街105号","石家庄","河北","103400");
emp. ChangeName ("王东");
cout<<emp.Display()<<end1;
}
第9题
阅读以下说明和C++程序,将应填入(n)处的字句写在对应栏内。
[说明]
本程序使用类来管理员工的通讯地址信息。已知程序的输出为:
输出记录:5
姓名:王丽华
街道地址:中华路15号
市:襄樊市
省;湖北省
邮政编码:430070
[C++程序]
include < iostream, h >
include < string, h >
class employee.
{ protected:
char name[10];
char street[ 20 ];
char city[10];
char (1) [10];
char post[7];
int no;
(2):
(3) (char [] ,char [] ,char [] ,char [] ,char [] ,int);
void changename (char n [] ) { strcpy (name, n); }
void changestreet(char s[] ) { strcpy(street,s) ;}
void changecity (char c [] ) { strcpy (city, c ); }
void changeprov(char p [] ) { strcpy(prov,p); }
void changeno(int nnm) { (4);}
void display();
};
employee:: (3) (char n[] ,char s[] ,char c[] ,char p1[] ,char p2[] ,int nam)
{ strcpy(name,n);
strcpy (street, s);
strcpy (city, c);
strcpy (prov, p1 );
strcpy (post, p2 );
no = nam; }
void employee:: display() { cont< <"输出记录: "< <no< <endl;
cout< < "姓名: "< < name < < endl;
coot < < "街道地址: "< < street < < endl;
cout < < "市: "< < city < < endl;
cout< <"省: "< <prov < <endl;
cout < <"邮政编码: "< < post < < endl;
}
void main() { employee cmp("王华" ,"中华路15号" ,"武汉市","湖北省","430070", 1 );
emp. changename("五丽华" );
emp. changecity ("襄樊市" );
emp. changeno(5);
(5);
第10题
Oxymoron , a rhetorical device, is based on antonymy.()
第11题
A.Admin > Device
B. Device Setup > Topology
C. Compression > Endpoints
D. Device Setup > Advanced > Topology
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