题目内容
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[单选题]
There are a number of problems underlying this ________ and apparently simple statem
A.conventional
B.innumerable
C.compact
D.concise
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A.number
B.name
C.time
更多“There are a number of problems…”相关的问题
第2题
Which statement can be an inference from the output？（）
A. The FRA disk group has an asynchronous I/O bottleneck
B. The least number of I/Os are performed on the last data file in the list
C. The number of times that the backup or restore process directed the OS to wait until an I/O was complete is the highest for the last data file in the list
D. The number of times that the backup or restore process made an OS call to poll for I/O completion in Nonblocking mode is the least for the FRA disk group
第3题
View the exhibit and examine the output.Which statement can be an inference from the output？（）
A. The FRA disk group has an asynchronous I/O bottleneck
B. The least number of I/Os are performed on the last data file in the list
C. The number of times that the backup or restore process directed the OS to wait until an I/O was complete is the highest for the last data file in the list
D. The number of times that the backup or restore process made an OS call to poll for I/O completion in Nonblocking mode is the least for the FRA disk group
第4题
What is the effect of increasing the value of the ASM_POWER_LIMIT parameter？（）
A. The number of DBWR processes increases
B. The number of ASMB processes increases
C. The number of DBWR_TO_SLAVES increases
D. The rebalancing operation in an ASM instance completes more quickly, but can result in higher I/O overhead
第5题
英译中The grand mediocrity of today－－everyone being the same in survival and number o
英译中
The grand mediocrity of today--everyone being the same in survival and number of offspring--means that natural selection has lost 80% of its power in upper-middle-class India compared to the tribe.
第6题
下面的算法是判断n是否为素数，其算法时间复杂度为（）。 void prime（int n) { 判断n是否是素数 */ for （i=2; i＜sqrt（n) && （n % i)!=0; i++) ; if （i＞sqrt（n)) printf（"%d is a prime number", n); else printf（"%d is not a prime number", n); }
A.O(n)
B.O(1)
C.O(sqrt(n)) sqrt表示对n取根方
D.O（n-i）
第7题
__-Yes,please.I need a skirt（）
A.Can I help you
B.How much is it
C.What's your telephone number
D.o you like apples
第8题
假设sqrt（n)函数中涉及的算法时间复杂度为O（1)，那么下面的算法是判断n是否为素数，其时间复杂度为（）。 void prime（int n) { for （i=2; i＜sqrt（n) && （n % i)!=0; i++) ; if （i＞sqrt（n)) printf（"%d is a prime number", n); else printf（"%d is not a prime number", n); }
A.O(n)
B.O(1)
C.O(sqrt(n)) sqrt表示对n取根方
D.O(n-i)
第9题
下面的算法是判断n是否为素数，其算法时间复杂度为（）。 void prime（int n) { 判断n是否是素数 */ for （i=2; i＜sqrt（n) && （n % i)!=0; i++) ; if （i＞sqrt（n)) printf（"%d is a prime number", n); else printf（"%d is not a prime number", n); }
A.O(n)
B.O(1)
C.O(sqrt(n)) sqrt表示对n取根方
D.O（n-i）
