题目内容
（请给出正确答案）
[单选题]
30、()
A.point
B.similarity
C.difficulty
D.difference
答案
D、difference
the difference between...and....意为“……和……之间的区别”。
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A．VC—AC
B．VC—SIMI
C．PC—BIPAP
D．SPN—CPAP
更多“()”相关的问题
第3题
You have a network that supports VLSM and you need to reduce IP address waste in your poin
t to point WAN links. Which of the masks below would you use？
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A. /38
B. /30
C. /27
D. /23
E. /18
F. /32
第4题
有如下程序：#include ＜iostream＞using namespace std;class point{intx,y;public:point（int vx,
有如下程序：#include ＜iostream＞using namespace std;class point{ int x, y;public: point(int vx, int vy ) { x = vx; y = vy; } point () x = 0; y= 0; } point operator+(point p1 ) { point p; int px = x+ p1.x; int py = y + p1.y; return point(px, py ); point operator-(point p1 ) { point p; int px = x -p1.x; int py = y - p1.y; return point (px, py ); } void print() { cout＜＜x＜＜" , "＜＜y＜＜end1; }};int main (){ point p1(10, 10 ), p2(20, 20 ); p1 = p1 - p2; p1.print (); return 0;} 执行后的输出结果是
A．10，10
B．20，20
C．10，20
D．30，30
第5题
有如下程序：#include ＜iostream＞using namespace std;class point{int x, y;public:point（int v
有如下程序：#include ＜iostream＞using namespace std;class point{ int x, y;public: point(int vx, int vy ) { X=vx; y=vy; } point() { x=0; y=0; } point operator+ (point p1 ) { point p; int px = x + p1.x; int py = y+ p1.y; return point(px, py ); } point operator-(point p1 { point p; int px = x - p1.x; int py = y - p1.y; return point(px, py ); } void print() { cout＜＜x＜＜","＜＜y＜＜end1; }};int main(){ point p1(10, 10 ), p2(20, 20 ); p1 = p1 + p2; p1.print(); return ();}执行后的输出结果是()。
A．10, 10
B．20, 20
C．10, 20
D．30, 30
第6题
有如下程序： #include ＜iostream＞ using namespace std; class point {int x,y; public:point（i
有如下程序： #include ＜iostream＞ using namespace std; class point { int x, y; public: point(int vx, int vy ) { x = vx; y = vy; } point () { x = 0; y = 0; } point operator+(point pl ) { point p; int px = x + p1.x; int py = y + p1.y; return point(px, py ); } point operator-(point p1 ) { point p; int px = x - p1.x; int py = y - p1.y; return point(px, py ); } void print() { cout＜＜x＜＜", "＜＜y＜＜end1; } }; int main () { point pl (10, 10 ), p2 (20, 20 ); p1 = p1 + p2; p1.print (); return 0; } 执行后的输出结果是()。
A．10,10
B．20,20
C．10,20
D．30,30
第7题
有如下程序：#include＜iostream＞using namespace std；class point{int x，y；public：point（int vx，i
有如下程序： #include＜iostream＞ using namespace std； class point { int x，y； public： point(int vx，int vy) { x=vx； y=vy； } point() { x=0； y=0； } point operator+(point p1) { point p； int px=x+p1.x； int py=y+p1.y； return point(px，py)； } point operator-(point p1) { point p； int px=x-p1.x； int py=y-p1.y； return point(px，py)； } void print() { cout＜＜x＜＜","＜＜y＜＜end1； } }； int main() { point p1(10，10)，p2(20，20)； p1=p1+p2； p1.print()； retrun 0； } 执行后的输出结果是
A．10，10
B．20，20
C．10，20
D．30，30
第8题
AP接入点（ACCESS POINT）是用于无线网络的无线HUB，是无线网络的核心。它是移动计算机用户进入有线以太网骨干的接入点，AP可以简便地安装在天花板或墙壁上，它在开放空间最大覆盖范围可达（）米，无线传输速率可以高达11Mbps。
A.3
B.30
C.300
D.3000
第9题
2015年12月大学英语六级作文预测11
For this part, you are allowed 30 minutes to write an essay commenting on the saying “The decisions that people make quickly are always wrong.” You can give an example or two to illustrate your point of view. You should write at least 150 words but no more than 200 words.
请给出范文，谢谢！
第10题
For this part, you are allowed 30 minutes to write an essay about the impact of theinform
ation explosion by referring to the saying "A wealth of information creates apoverty of attention. " You can give examples to illustrate your point and then explainwhat you can do to avoid being distracted by irrelevant information. You shouldwrite at least 150 words but no more than 200 words. ___________________________________________________________________________________________________________________________________________________________ ___________________________________________________________________________________________________________________________________________________________ ___________________________________________________________________________________________________________________________________________________________
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第11题
30、关于内能做功，以下说法正确的是___ The following statement about Internal Energy doing Work is true___
A.荡秋千时，会荡秋千的人到最高点时站直，到最低点时蹲下，秋千会越荡越高； When playing on a Swing, the person who plays on a Swing will stand up straight at the highest point and squat down at the lowest point;#B.荡秋千时，会荡秋千的人到最高点时蹲下，到最低点时站直，秋千会越荡越高； When playing on a Swing, the person who plays on a Swing will crouch down at the highest point and stand up straight at the lowest point. The Swing will go higher and higher;#C.荡秋千时，不会荡秋千的人到最高点时站直，到最低点时蹲下，秋千会逐渐停止； In a Sw
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