题目内容（请给出正确答案）

[单选题]

I（）half of the English novel,and l'll try to finish it at the weekend.()。

A.read

B.have read

C.am reading

D.will read

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更多“I（）half of the English novel,a…”相关的问题

第1题

Please wait here. I'll be back in ______ hours. A) two and half an B) two and a half C) half a

Please wait here. I'll be back in ______ hours.

A) two and half an B) two and a half C) half and two D) two a half

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第2题

I could buy my ticket after queuing for half an hour. （)

I could buy my ticket after queuing for half an hour. ()

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第3题

As I had worked more than half hour, I was a little tired.（)

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第4题

－－－ ____？一It’s half past seven.A.What time is it nowB.Can I help youC.Where are yougoin

--- ____？

一It’s half past seven.

A.What time is it now

B.Can I help you

C.Where are yougoing

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第5题

I’ve lived here for about _______.A.two and a half yearB.two and a half yearsC.two year

A.two and a half year

B.two and a half years

C.two year and a half

D.two years and half

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第6题

I have ___ only half of what I hoped to do.

A.accomplished

B.completed

C.achieved

D.finished

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第7题

Charles is now an actor. ______（give)half a chance I would have been the same.

Charles is now an actor. ______(give)half a chance I would have been the same.

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第8题

I ____________ home at half past six.

A.was at

B.come at

C.arrive in

D.go to

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第9题

符号三角形问题的回溯算法如下 half=（n+1）*n/4; // （n+1)*n/2是偶数 void backtrack （int t) { if （（count＞half)||（t*（t-1)/2-count＞half)) return; if （t＞n) sum++; else for （int i=0;i＜2;i++) { p[1][t]=i; count+=i; for （int j=2;j＜=t;j++) { p[j][t-j+1]=p[j-1][t-j+1]^p[j-1][t-j+2]; count+=p[j][t-j+1]; }backtrack（t+1); for （int j=2;j＜=t;j++) count-=p[j][t-j+1]; count-=i; } } 现要求将红色代码去掉，保持算法功能不改变，需在添加下面哪段代码

A.if ((count＞half)||(t*(t-1)/2-count＞half))

B.if ((count＜=half)&&(t*(t-1)/2-count＜=half))

C.if ((count＜=half)&&(t*(t+1)/2-count＜=half))

D.if ((count＞half)||(t*(t+1)/2-count＞half))

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第10题

Having worked hard for half a year, I plan to go on my （).A.vocation B.vacation C.cau

Having worked hard for half a year, I plan to go on my ().

A.vocation

B.vacation

C.caution

D.action